Use implicit differentiation to find the slope of the tangent line to the curve y/(x-2y) = y^3 +9 (1,10/21)

ive done this problem around 10 times and i still cant get it....
when i did it the last time i got -9-y^3/ 3y^2 x - 8y^3 - 19
and the slope around 0.4754 but it is still wrong i don't know what i am doing wrong..

The point (1, 10/21) is not on the curve. Plug in x = 1 and y = 10/21 and you will see that the equation is not satisfied. Are you sure you stated the problem correctly?

Looks like it should be

y/(x-2y) = x^3 +9

To find the slope of the tangent line to the curve at the given point, we need to use implicit differentiation. Let's go through the steps together:

1. Start with the given equation: y / (x - 2y) = y^3 + 9.

2. Differentiate both sides of the equation with respect to x. We treat y as a function of x and use the chain rule for the terms involving y. Remember, when differentiating y with respect to x, we need to include dy/dx.

d/dx(y / (x - 2y)) = d/dx(y^3 + 9).

3. For the left-hand side, we use the quotient rule:

[(x - 2y) * (d/dx(y))] - [y * (d/dx(x - 2y))] / (x - 2y)^2 = 3y^2 * (dy/dx).

4. Simplify the left-hand side first:

[(x - 2y) * (dy/dx)] - [y * (1 - 2(dy/dx))] / (x - 2y)^2 = 3y^2 * (dy/dx).

Now, we need to isolate dy/dx, which represents the slope of the tangent line.

5. Multiply both sides by (x - 2y)^2:

(x - 2y) * [(x - 2y) * (dy/dx)] - y * (1 - 2(dy/dx)) = 3y^2 * (dy/dx) * (x - 2y)^2.

Simplify the left-hand side further:

(x - 2y)^2 * (dy/dx) - (2y - y + 2y * (dy/dx)) = 3y^2 * (dy/dx) * (x - 2y)^2.

Expand and group similar terms:

(x - 2y)^2 * (dy/dx) - (y + 2y * (dy/dx)) = 3y^2 * (dy/dx) * (x - 2y)^2.

Combine like terms:

(x - 2y)^2 * (dy/dx) - 3y * (dy/dx) = 3y^2 * (dy/dx) * (x - 2y)^2.

6. Factor out (dy/dx):

[(x - 2y)^2 - 3y] * (dy/dx) = 3y^2 * (dy/dx) * (x - 2y)^2.

7. Divide both sides by [(x - 2y)^2 - 3y]:

(dy/dx) = [3y^2 * (dy/dx) * (x - 2y)^2] / [(x - 2y)^2 - 3y].

Now we have the expression for dy/dx (the slope of the tangent line) in terms of x and y. To find the slope at the point (1, 10/21), substitute x = 1 and y = 10/21 into the expression for dy/dx.

Let's plug in the values and calculate the slope.