Algebra 2

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Solve each equation below for x. (Use logarithms.)

10^(2x^(2)-5x+11) = 10000

9^(2(x-1)) = √(27)

  • Algebra 2 -

    just undo the operations, one by one:

    10^(2x^(2)-5x+11) = 10000
    take log base 10
    2x^(2)-5x+11 = log10000 = 4
    2x^2 - 5x + 7 = 0
    (2x-7)(x+1) = 0
    . . .

    9^(2(x-1)) = √(27) = 3^(3/2) = 9^(3/4)
    take log base 9
    2(x-1) = 3/4
    8x-8 = 3
    8x = 11
    . . .

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