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Express the concentration of a 0.0510 M aqueous solution of fluoride, F-, in mass percentage and in parts per million. Assume the desnity of the solution is 1.00 g/mL

Since, we're assuming the density I think that also means were assuming the volume.. but where would you go from there? please help!

  • Chemistry -

    I don't know to agree or disagree about the volume since you don't say what you are assuming about the volume.
    0.0510 M means 0.0510 moles/L soln.
    0.0510 mol x 19 g F^-/mol = about 0.969 g/L soln.
    Since the density of the soln is 1.00 g/mL, then this is 0.969 g F^-/1000 g soln
    % w/w = (0.969g/1000g)*100 = 0.0969%.

    For ppm, I find the factor 1 ppm = 1 mg/L to be useful.
    0.000969 g/mL x (1000mg/g) = 0.969 mg/mL x (1000 mL/L) = 969 g/L = 969 ppm.
    Check all of this carefully.

  • Chemistry -

    yes that was correct! thank you

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