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Algebra 2

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2^(3x+1)=2^)2/x) I don't know what to do here to get both of the xs

  • Algebra 2 -

    Since you have the same base, do this:

    3x + 1 = 2/x

    Now we can solve for x:

    x(3x + 1) = x(2/x) -->multiplying both sides by x to get rid of x in the denominator. (Whatever operation you do to one side of an equation you must do to the other side as well.)

    3x^2 + x = 2

    Set the equation equal to 0:
    3x^2 + x - 2 = 0

    Try to factor:
    (3x - 2)(x + 1)

    Set each factor equal to 0 and solve for x:
    3x - 2 = 0; x = 2/3
    x + 1 = 0; x = -1

    You have two possible solutions. Check these with the original equation. It always helps to check your work!

    I hope this helps.

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