Chemistry
posted by David .
at 25C and 795 torr, carbon dioxide has a solubility of 0.0356 M in water. What is the solubility at 25 C and 2070 torr? ____ M
I know that at a given temperature, the solubility of a gas in a liquid is directly proportional to its pressure but how would that be set up in an equation..?

Hello, I think that this should help.
chem.queensu.ca/people/faculty/mombourquette/firstyrchem/solubility/index.htm 
You are exactly right. You set it up this way.
0.0356M x (2070 torr/795 torr) = ?
If you want to do real scientifically, the equation is
p = kc.
We evaluate k = p/c and plug in the first set of conditions.
k = 795/0.0356 = 22,331
Then p = kc and solve for c
c = p/k = 2070/22,331 = = ?
You should obtain the same answer. 
Thanks guys!