posted by chem .
How to find the %(W/V) of 134mL of a 0.610 M solution of Mg(OH)2
0.610M means 0.610 moles/L soln or 0.0610 moles/100 mL.
mol Mg(OH)2 = grams Mg(OH)2/molar mass. You know molar mass and moles, solve for grams. That many grams/100 mL is the w/v %.