Q1) For the reaction, A to B,

Delta H= +11.00 kJ mol-1 and Keq is 12.50

Calculate i) delta G and ii) delta S at 25 C (degrees celcius)

0 C degrees celcius = 273.15 K; R = 8.314 J K-1 mol-1] PLease help dr bob222

If you have answers to these two problems I may be able to help.

I don't have answers could u still try to help me

Jenny, I believe a wrong answer is worse than no answer at all. You might look at this possibility.

dGo = -RTlnK
You have K, you find dGo from that.

Since this is at 25C, dG MAY be dGo and
dG = dH-TdS.
Substitute dG and dH and solve for dS.
Let me know if this works out.

To calculate delta G and delta S for the reaction A to B, we can use the following formulas:

1) delta G = -RT ln(Keq)
2) delta G = delta H - T delta S

Let's calculate each value step by step:

i) delta G:
Using the equation (1), we substitute the given values:

delta G = -RT ln(Keq)
= - (8.314 J K-1 mol-1) * (273.15 + 25) K * ln(12.50)

Calculating this expression will give you the value for delta G.

ii) delta S:
Using equation (2), we rearrange it to solve for delta S:

delta S = (delta H - delta G) / T

Substituting the given values:

delta S = (11.00 kJ mol-1 - delta G) / (273.15 + 25)

Again, calculating this expression will give you the value for delta S.