Q1) For the reaction, A to B,
Delta H= +11.00 kJ mol-1 and Keq is 12.50
Calculate i) delta G and ii) delta S at 25 C (degrees celcius)
0 C degrees celcius = 273.15 K; R = 8.314 J K-1 mol-1] PLease help dr bob222
If you have answers to these two problems I may be able to help.
I don't have answers could u still try to help me
Jenny, I believe a wrong answer is worse than no answer at all. You might look at this possibility.
dGo = -RTlnK
You have K, you find dGo from that.
Since this is at 25C, dG MAY be dGo and
dG = dH-TdS.
Substitute dG and dH and solve for dS.
Let me know if this works out.
To calculate delta G and delta S for the reaction A to B, we can use the following formulas:
1) delta G = -RT ln(Keq)
2) delta G = delta H - T delta S
Let's calculate each value step by step:
i) delta G:
Using the equation (1), we substitute the given values:
delta G = -RT ln(Keq)
= - (8.314 J K-1 mol-1) * (273.15 + 25) K * ln(12.50)
Calculating this expression will give you the value for delta G.
ii) delta S:
Using equation (2), we rearrange it to solve for delta S:
delta S = (delta H - delta G) / T
Substituting the given values:
delta S = (11.00 kJ mol-1 - delta G) / (273.15 + 25)
Again, calculating this expression will give you the value for delta S.