maths
posted by chrystabelle .
express x1/(x+1)(x2)^2 into partial fractions

let
(x1)/((x+1)(x2)^2) = A/(x1) + B/(x2) + C/(x2)^2
multiply both sides by (x+1)(x2)^2
A(x2)^2 + B(x2)(x+1) + C(x+1) = x1
let x = 2, > 3C = 1 or C=13
let x = 1 > 9A + 2 or A = 2/9
let x = 0 > 4A  2B + C = 1
4(2/9)  2B + 1/3 = 1
times 9
8  18B + 3 = 9
B = 2/9
so (x1)/(x2)^2 = 2/(9(x+1)) + 2/(9(x2)) + 1/(3(x2)^2)
verified with Wolfram:
http://www.wolframalpha.com/input/?i=%28x1%29%2F%28%28x%2B1%29%28x2%29%5E2%29 
in the middle of the solution above the line should read:
et x = 2, > 3C = 1 or C=1/3
Respond to this Question
Similar Questions

Maths
Resolve into partial fractions: (x+3)(x+1)/ x(x^2+x+1) Can anyone please help me out? 
Binomial
Help me on this one :( Express y= (73xx^2)/[((1x)^2)(2+x)] in partial fractions. Hence, prove that if x^3 and higher powers of x may be neglected, then y=(1/8)(28+30x+41x^2) I did the first part of expressing it in partial fractions. … 
maths
Resolve 3x/x^2x12 into partial fractions 
Math Partial Fractions
Decompose the following into partial fractions after factoring the denominator as much as possible. Please show some work so I can understand how you did it. 1)x^2/((x1)(x^2+5x+4)) 2)(3x^35x^2+12x+4)/(x^416) 3)1/(x^2 (x+1)^2 ) 4)(x+1)/((x^2+1) … 
math
Express (5x+2)/(2x1)(x+1) into partial fractions and hence expand the expression as a series in ascending power of x giving the first 4 terms 
math/algebra
Express x^2  3x/x^2  1 As partial fractions 
Math
Express 1315x^2/(x^21)(x 3) into partial fractions 
maths partial fractions
Resolve in partial form (x^2+15)/(x+3)^2(x^2+3) 
Math
Express 2x^39/x^3+6x^2+8x as partial fractions 
Alex
Express x^34/x^2(x+2) into partial fractions