Calculusderivatives
posted by Jake .
What is the slope of the tangent of each curve at given point
y=√(16x^3), (4,32)
If I find the derivative of y=√(16x^3)
Will it be 16/x^3

nope. √x^3 = x^(3/2)
so,
y = √16x^3 = 4x^(3/2)
y' = 4(3/2)x^(1/2) = 6√x
y'(4) = 6√4 = 12
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