Physics
posted by Kaiz .
Mercury has a density of 13600 kg/m3. At what depth in millimetres is the pressure in mercury equal to that of standard atmospheric pressure? (take std pressure= 101 Pa)

Pressure = height * density * gravity
101 Pa = height * (13600 kg / m3) * (9.81 m/s2)
** note that kg * m/s2 = N
101 Pa = height * 133416 N/m3
** Pa = N/m2
therefore,
(101 N/m2) / (133416 N/m3) = height
height = 0.00075703 m = 0.75703mm
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HOWEVER!!! from my knowledge the standard atmospheric pressure is 101.325 KILO Pascal... so if that's the case, assuming you mistyped and meant 101 kPA...
101 kPa = height * 133416 N/m3
(101000 N/m2) / (133416 N/m3) = height
height = 0.757030641 m = 757.030641 mm
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