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2. Solve this equation: 80 = 3y + 2y + 4 + 1.

A. y = –15
B. y = 1/5
C. y = 75
[D. y = 15]
i don't realy know if that is correct because i think it could be negative like in a please let me know

  • jake -

    80 = 3y + 2y + 4 + 1.

    80 = 5y + 5

    80 - 5 = 5y

    75 = 5y

    75/5 = y

    Yes. D is correct.

    15 = y

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