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Algebra

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The bongo family has three children, including a pair of twins. The third child is 3 years younger then the twins. The sum of the three ages is 42. How old is each child?

  • Algebra -

    a = age of the twins

    b = age of the third child


    b = a - 3


    a + a + b = 42

    2 a + b = 42

    2 a + a - 3 = 42


    3 a - 3 = 42

    3 a = 42 + 3

    3 a = 45 Divide both sides by 3

    a = 45 / 3

    a = 15


    b = 15 - 3

    b = 12

  • Algebra -

    the first of two films lasted 9 minutes less than twice as long as the second. the combined length of the two films plus a 5-minute break between them was 260 minutes. how long was the first film?

  • Algebra -

    x + 2x - 9 + 5 = 260

    3x - 4 = 260

    3x = 264

    x = 88

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