posted by Mike .
In a particular redox reaction, Cr is oxidized to CrO4^2– and Cu2^+ is reduced to Cu^+ . Complete and balance the equation for this reaction in acidic solution.
Cr + Cu^2+ ---> CrO4^2-+ Cu^+
i started off by doing this
2 x SO3^2- ---> SO4^2- + 2e
2 x Cu^2+ +2e ---> Cu^+
2SO3^2- ---> 2SO4^2- +4e
2Cu^2+ + 4e ----> 2Cu^+
the 4e cancel out and we got
2SO3^2- +2Cu^+ ----> 2SO4^2- + 2Cu^+
Please tell me if i did the process the wrong way. The prof hasn't started this topic but i just wanted to try it out.
I can tell you with some assurance that you will never balance chromate by using sulfite to sulfate. Here is a web site that will help you.
oh no i messed up ! i wrote the wrong elements -_-'' im sorry.And thanks for the website!