MATH
posted by Anonymous .
Find an equation of the line that is tangent to the graph of f and parallel to the given line.
Function
f(x) = 2x^2
Line
6x – y + 4 = 0

f'(x) = 4x
slope of given line = 6
so
4x = 6
x = 3/2
then y = 9/2
since new line is parallel to old line, it should look like
6x y= K
plug in point (3/2, 9/2)
6(3/2) 9/2 =k
k = 9/2
so 6x  y = 9/2, or
12  2y = 9
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