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Find an equation of the line that is tangent to the graph of f and parallel to the given line.
Function
f(x) = 2x^2

Line
6x – y + 4 = 0

  • MATH -

    f'(x) = 4x
    slope of given line = 6
    so
    4x = 6
    x = 3/2
    then y = 9/2

    since new line is parallel to old line, it should look like
    6x- y= K
    plug in point (3/2, 9/2)
    6(3/2) -9/2 =k
    k = 9/2
    so 6x - y = 9/2, or
    12 - 2y = 9

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