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A proton has an initial speed of 3.9×105 m/s.

What potential difference is required to bring the proton to rest?

What potential difference is required to reduce the initial speed of the proton by a factor of 2?

What potential difference is required to reduce the initial kinetic energy of the proton by a factor of 2?

  • physics -

    Figure initial kinetic energy (1/2) m v^2
    (ok because speed well below that of light)

    volts * charge = energy = (1/2) m v^2

    I guess you can divide v by two and v^2 by 2

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