calculus
posted by Anonymous .
Find the surface area of the solid generated by rotating the area between the yaxis, (x^2/y) + y = 1, and 1≤y≤0 is rotated around the yaxis.

you have a circle:
x^2 + (y1/2)^2 = 1/4
except that as originally written, y cannot be zero.
Now, since the range of y is (0,1], there is no part of the graph below the xaxis. Note that any y < 0 will produce a value such that (y1/2)^2 > 1/4. That means that x^2 must be negative.
Is this a trick question?
If there's a typo, and you want 0<y<=1, then you are just rotating a semicircle of radius 1/2, whioch will give you a sphere.
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