physics
posted by Natasha .
A 20kg sled is being pulled across a horizontal surface at a constant velocity. The pulling force has a magnitude of 80N and is directed at a angle of 30.0degrees above the horizontal. Determine the coefficient of kinetic friction.

Ws = mg = 20 * 9.8N/kg = 196 N. = Wt. of sled.
Fs = 196N. @ 0 Deg. = Force of sled.
Fp = 196*sin(00 = 0 = Force parallel to
surface.
Fv = 196*cos(0) = 196 N. = Force perpendicular to surface.
Fap  Fp  Fk = 0,
80*cos30  0 u(19680*sin30) = 0,
69.3  u*156 = 0,
156u = 69.3,
u = 69.3 / 156 = 0.444. 
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