posted by jessica .
A golf ball is struck with a five iron on level ground. It lands 92.7 m away 4.40 s later. What was (a) the direction and (b) the magnitude of the initial velocity?
a. Xo*t = Dx = 92.7 m.
Vo*4.40 = 92.7,
Xo = 92.7 / 4.40 = 21.07 m/s. = hor component of initial velocity.
Yf = Yo + gt
Yo = Yf - gt,
Yo = 0 - (-9.8)(4.4/2) = 21.56 m/s. =
ver. component of initial velocity.
tanA = Yo/Xo = 21.56 / 21.07 = 1.02326.
A = 45.7 Deg. = Direction of initial velocity.
b. Vo=Xo/cosA=21.07/cos45.7=30.15m/s =
Magnitude of initial velocity.