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A solution of 0.178 M KOH(28.3 ml) is mixed with 28.9ml of 0.133 M HCl. Assuming that the final solution is the sum of the initial volumes, caculate:

a)the molarity of the K+ cation
b)the molatiry of the Cl- anion
c)the pH of the final solution
d)the pOH of the final solution

  • chemistry -

    moles KOH = M x L = ?
    moles HCl = M x L = ?
    All K^+ come from KOH. All Cl^- come from HCl.
    a. (K^+) = moles K^/L soln
    b. (Cl^-) = moles Cl^-/L soln.
    c. KOH + HCl ==> KCl + H2O
    (H^+) or (OH^-) is determined by which reagent is in excess. Subtract the moles and see which is in excess and convert to pH or pOH.
    Post your work if you get stuck.

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