A sample of Nitrogen is collected over water at 26 Celsius. What is the partial pressure of nitrogen if the total pressure is 99.4 kPa and the partial pressure of water vapor at 26 Celsius is 25 torr
This is worked the same as the last problem except the units are not the same. You must convert kPa to torr or torr to kPa.
To calculate the partial pressure of nitrogen, we first need to convert the pressure of water vapor from torr to kilopascals.
1 torr is equal to 0.133322 kilopascals (kPa). So, the pressure of water vapor in kilopascals is calculated as follows:
Pressure of water vapor (kPa) = 25 torr * 0.133322 kPa/torr = 3.33305 kPa
Next, we need to subtract the pressure of water vapor from the total pressure to find the partial pressure of nitrogen:
Partial pressure of nitrogen (kPa) = Total pressure - Pressure of water vapor
Partial pressure of nitrogen (kPa) = 99.4 kPa - 3.33305 kPa
Partial pressure of nitrogen (kPa) = 96.06695 kPa
Therefore, the partial pressure of nitrogen is approximately 96.06695 kPa.