How many grams of magnesium metal are produced by the decomposition of 19 grams of magnesium chloride?
Just follow the steps.
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To determine the number of grams of magnesium metal produced by the decomposition of magnesium chloride, we need to consider the balanced chemical equation for the reaction.
The balanced equation for the decomposition of magnesium chloride is:
2 MgCl2 -> 2 Mg + Cl2
From this equation, we can see that every 1 mole of magnesium chloride (MgCl2) produces 2 moles of magnesium metal (Mg). We can use this ratio to calculate the number of moles of magnesium metal produced.
First, let's calculate the number of moles of magnesium chloride using its molar mass. The molar mass of magnesium chloride (MgCl2) is approximately 95.211 grams/mol (24.305 grams/mol for Mg + (2 × 35.453 grams/mol for Cl)).
Number of moles of MgCl2 = 19 grams / 95.211 grams/mol = 0.1996 moles
Now, using the ratio from the balanced equation, we can determine the number of moles of magnesium metal produced:
Number of moles of Mg = 0.1996 moles × (2 moles of Mg / 2 moles of MgCl2) = 0.1996 moles
Finally, we can convert the moles of magnesium metal into grams by multiplying by its molar mass. The molar mass of magnesium (Mg) is approximately 24.305 grams/mol.
Number of grams of Mg = 0.1996 moles × 24.305 grams/mol = 4.847 grams
Therefore, approximately 4.847 grams of magnesium metal are produced by the decomposition of 19 grams of magnesium chloride.