# intermediate algebra

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A triangle is such that the largest angle is 11 times the smallest angle. The third angle is 27° less than the largest angle. Find the measure of each angle. (Enter solutions from smallest to largest.)

• intermediate algebra -

Let x = smallest angle, then 11x = largest and 11x - 27º is the third.

x + 11x + (11x-27º) = 180º

Solve for x, then the other angles.

• intermediate algebra -

x^2-25/x^2+11x+24

• intermediate algebra -

Let the smallest angle be x
Then the largest angle is 11x
Therefore the third angle is 11x-27 as the
Third angle is 27 less than the largest angle.
By angle sum property of a triangle we get
X +11x+11x-27 =180 degrees
By simplification,
23x-27=180 degrees
23x=180+27=207
X=207/23
X=9 degrees
We clearly get the angles as 9,99,72

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