# calculus

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Find the equation of the tangent line to the curve y=sqrt(x) at x = c. Put the answer in slope intercept form y=mx+b. Use the definition of the slope of the tangent with no short cuts.

• calculus -

so the point of contact is (c, √c)

y = √x = x^(1/2)
dy/dx = (1/2)x^(-1/2)
at our point
dy/dx = (1/2)c^(-1/2) = 1/(2√c) = slope = m

y = (1/(2√c) x + b
at(c, √c)
√c = (1/(2√c)(c) + b
times 2√c
2c = c + 2√c b
c = 2√c b
b = c/√c

y = (1/(2√c)) x + c/√c

check my arithmetic
You could rationalize the denominator if you had to.

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