Post a New Question


posted by .

Two charges of equal magnitude of 2C and mass of 1.0 g are separated by a distance of 3 mm. Find the velocity of one particle when they are separated by a distance of 4mm.

  • Physic -

    Are both particles free to move? Was the velocity 0 when they were 3 mm apart?

    If so, they move at equal velocity in opposite directions. Use conservation of energy and the change in electrostatic potential energy to compute the increase in kinetic energy.

    kQ^2/0.003m - kQ^2/0.004m = 2*(1/2) M V^2

    M = 0.001 kg
    k is the Coulomb constant

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question