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Trig

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Prove (1+secx)/(tanx+sinx)=cscx

  • Trig -

    Answered in another post.

  • Trig -

    tan ( x ) = sin ( x ) / cos ( x )


    tan ( x ) + sin ( x ) =

    sin ( x ) / cos ( x ) + sin ( x ) =

    sin ( x ) * [ 1 / cos ( x ) + 1 ] =

    sin ( x ) * [ sec ( x ) + 1 ] =

    sin ( x ) * [ 1 + sec ( x )]



    [ 1 + sec ( x ) ] / [ tan ( x ) + sin ( x ) ] =

    [ 1 + sec ( x ) ] / [ sin ( x ) * [ 1 + sec ( x ) ] ] =

    1 / sin ( x ) = cosec ( x )

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