Calculus
posted by Anonymous .
A pomegranate is thrown from ground level straight up into the air at time t=0 with velocity 128 feet per second. Its height in feet at t seconds is f(t)=16t^2+128t. Find the time its hits the ground and the time it reaches its highest point.

Your equation should be
f(t) =  16t^2 + 128t
so
16t^2 + 128t = 0
t^2  8t = 0
t(t8) = 0
t = 0 > when you tossed it
t = 8 > when it lands
so it reached the hightest point at the midpoint of that 8 seconds, namely at 4 seconds
f(4) = 16(4^2) + 128(4)
= 256 ft
Wow!, That is quite a feat to through a pomegranate 256 feet into the air!!!!!