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A water pistol aimed horizontally projects a stream of water with an initial speed of 5.00 m/s.
(a) How far does the water drop in moving 1.00 m hori-
(b) How far does it travel before dropping a vertical
distance of 1.00 cm?


    (a) It takes
    t = 1.00/5.00 = 0.2 seconds
    to travel 1.0 meter horizontally.

    Use the formula
    (elevation change) = (g/2) t^2

    (b) To fall 1.00 cm, the time required is
    given by
    0.01 = (g/2) t^2
    t = 0.0452 s
    The horizontal distance traveled by the water in that time is
    5*0.0452 meters


    .2 seconds


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