# physics

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A bomb is dropped from a height of 40m.simultaneously and vertically below it,a second bomb is fired vertically with a velocity of 20m/s.At what distance from the ground do they collide

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(1) Write equations for the height of each bomb vs t,
(2) Set then equal and solve for t.
(3) Use that t and either height equation to solve for location

Y1 = 40 -4.9 t^2
Y2 = 20t - 4.9 t^2

Y1 = Y2 when t = 2 seconds

Solve for either Y.

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