# PHYSICS

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A ball is thrown from a point 1.1 m above the ground. The initial velocity is 20.3 m/s at an angle of 32.0° above the horizontal.

(a) Find the maximum height of the ball above the ground???

(b) Calculate the speed of the ball at the highest point in the trajectory???

• PHYSICS -

Vo = 20.3 m/s @ 32 Deg.
Xo = 20.3*cos32 = 17.2 m/s.
Yo = 20.3*sin32 = 10.76 m/s.

a. hmax = 1.1 + (Yf^2-Yo^2/2g,
hmax=1.1 + (0-(10.76)^2) / -19.6=7.0 m.

b. Yf = 0 @ hmax.

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