Algebra(please Proof Read

posted by .

P(x)= -.1(100)^2 +50(100)+300= 3,700,000
P(x)= -.1(150)^2 +50(150) +300= 4,950,000
P(x)= -.1(250)^2 +50(250) +300= 5,950,000
P(x)= -.1(350)^2 +50(350) +300= 4,950,000
P(x)= -.1(450)^2 +50(450) +300= 1,950,000

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. accounting 2 urgent please help

    part 1 June 30, 2008/2007 Assets Cash- 34,700/23,500 accounts receivable- 101,600/92,300 inventory- 146,300/142,100 Investment-0/50,000 Land-145,000/0 equipment- 215,000/175,500 accumulated depreciation- (53,400)/ (41,300) 2008= 594,000 …
  2. Math

    These are my steps but I don't think I did it the right way. 1,300,000 ^ 18.6% of ?
  3. Economics

    During a year of operation, a firm collects $450,000 in revenue and spends $100,000 on labor expense, raw materials, rent, and utilities. The firm's owner has provided $750,000 of her own money instead of investing the money and earning …
  4. Accounting

    What is your margin tax rate________ and what is your average tax rate_________?
  5. Accounting

    What is your margin tax rate________ and what is your average tax rate_________?
  6. Physical science

    If you could produce a sample containing 2,400,000 free neutrons, what would it be 2658 seconds later?
  7. physics

    you could produce a sample containing 2,400,000 free neutrons, what would it be 2658 seconds later?
  8. Algebra

    Please Check these P(x)= -.1(100)^2 +50(100)+300= 3,700,000 P(x)= -.1(150)^2 +50(150) +300= 4,950,000 P(x)= -.1(250)^2 +50(250) +300= 5,950,000 P(x)= -.1(350)^2 +50(350) +300= 4,950,000 P(x)= -.1(450)^2 +50(450) +300= 1,950,000
  9. Math/Accounts

    Estimate the cost of ending inventory based on the retail method using the following information: Cost Retail Beginning Inventory $ 600,000 $ 800,000 Purchases $ 450,000 $ 600,000 Net Sales $1,000,000 A. $150,000 B. $262,500 C. $300,000 …
  10. Finance

    Given an interest rate of 6.25% compounded annually, how much would you accumulate if you started with $3,250 and then contributed $1,950 per year (at the end of each year) for 13 years?

More Similar Questions