How many grams of CO2 are formed when 32 g of O2 reacts with 23 g of C2H5OH?
This is a limiting reagent problem. I know that because amounts are given for BOTH reactants.
1 Write and balance the equation.
2. Convert g O2 t mols. mols = grams/molar mass
3. Convert g C2H5OH to moles.
4a. Using the coefficients in the balanced equation, convert moles oxygen to moles CO2.
4b. Same procedure, convert mols C2H5OH to moles CO2.
4c. Both answers can't be right; the correct one in limiting reagent problems is ALWAYS the smaller value.
5. Using the smaller value, convert moles CO2 to grams. g = moles x molar mass.
i know nothing
To determine the amount of CO2 formed when 32 g of O2 reacts with 23 g of C2H5OH, we need to set up a balanced chemical equation for the reaction and then use stoichiometry to find the mass of CO2 produced.
The balanced chemical equation for the reaction between C2H5OH (ethanol) and O2 (oxygen) to form CO2 (carbon dioxide) and H2O (water) is:
C2H5OH + 3O2 → 2CO2 + 3H2O
Now, we can calculate the molar masses of each compound:
Molar mass of C2H5OH: 2(12.011 g/mol) + 6(1.008 g/mol) + 16.00 g/mol + 1.008 g/mol = 46.069 g/mol
Molar mass of O2: 2(16.00 g/mol) = 32.00 g/mol
Molar mass of CO2: 12.011 g/mol + 2(16.00 g/mol) = 44.011 g/mol
Next, we convert the given masses to moles:
Moles of C2H5OH = 23 g / 46.069 g/mol = 0.4995 mol
Moles of O2 = 32 g / 32.00 g/mol = 1.0 mol
From the balanced equation, we can see that the stoichiometric ratio between C2H5OH and CO2 is 1:2. Therefore, the number of moles of CO2 formed is twice the number of moles of C2H5OH:
Moles of CO2 = 0.4995 mol × 2 = 0.999 mol
Finally, we can calculate the mass of CO2 formed by multiplying the number of moles by the molar mass:
Mass of CO2 = 0.999 mol × 44.011 g/mol = 43.963 g
Therefore, approximately 43.963 grams of CO2 are formed when 32 g of O2 reacts with 23 g of C2H5OH.
To determine the number of grams of CO2 formed when O2 reacts with C2H5OH, we need to find the balanced chemical equation for the reaction, and then use stoichiometry to calculate the amount of CO2 produced.
The balanced chemical equation for the reaction between O2 and C2H5OH is:
C2H5OH + 3O2 -> 2CO2 + 3H2O
From the balanced equation, we can see that for every 1 mole of C2H5OH, 2 moles of CO2 are produced.
First, let's find the number of moles of O2 and C2H5OH using their respective molar masses:
Molar mass of O2 = 32 g/mol
Number of moles of O2 = mass of O2 / molar mass of O2 = 32 g / 32 g/mol = 1 mol
Molar mass of C2H5OH = (12.01 g/mol × 2) + (1.01 g/mol × 6) + (16.00 g/mol + 1.01 g/mol + 1.01 g/mol) = 46.07 g/mol
Number of moles of C2H5OH = mass of C2H5OH / molar mass of C2H5OH = 23 g / 46.07 g/mol ≈ 0.5 mol
Since the balanced equation shows that 1 mole of C2H5OH produces 2 moles of CO2, we can calculate the number of moles of CO2 produced:
Number of moles of CO2 = number of moles of C2H5OH × (2 moles of CO2 / 1 mole of C2H5OH)
= 0.5 mol × 2 mol/mol = 1 mol
Finally, we can find the mass of CO2 produced by multiplying the number of moles of CO2 by its molar mass:
Molar mass of CO2 = (12.01 g/mol × 1) + (16.00 g/mol × 2) = 44.01 g/mol
Mass of CO2 = number of moles of CO2 × molar mass of CO2
= 1 mol × 44.01 g/mol
= 44.01 g
Therefore, when 32 g of O2 reacts with 23 g of C2H5OH, approximately 44 grams of CO2 are formed.