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A dynamite blast at a quarry launches a chunk of rock straight upward, and 2.0s later it is rising at a speed of 15m/s. Assuming air resistance has no effect, calculate its speed A) at launch and B) 5.0s after lauch

  • physics -

    v = Vi - 9.8 t
    15 = Vi - 19.6
    Vi = 34.6 s
    so
    v = 34.6 - 9.8 t
    You can do that for t = 5

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