Precalculus
posted by Melinda .
Explain how to do these please.
1. solve x=log(base2)*1/8 by rewriting in exponential form.
2. Solve log(3x+1)=5
3. Solve log(base x)8=1/2

x = log2 (1/2)^3
x = 3 log2 (1/2)
x/3 = log 2(1/2) = log 2 (1)  log2(2)
but log2 (1) = 0 and log 2 (2) = 1
so
x/3 = 1
x = 3 
log(3x+1)=5
I get we mean log base 10
10^log(3x+1) = 3x+1
so
3x+1 = 10^5
3 x = 10^5 1 = 9999
x = 3333 
log(base x)8=1/2
x^log(base x)8 = 8
so
8 = x^(1/2) = 1/sqrt x
sqrt x = 1/8
x = 1/64
Respond to this Question
Similar Questions

check!
here is the question: log5(x4)= log7x solve for x. These are just base 10 logs. log100 = 2 This equation has the same format as log 40 = log (2x20) Since both sides have log base 10, you divide by log base 10 and end up with 5(x4) … 
math
solve for x without using a calculator 5^(x+1) = 25 i know that x would equal 1 because 5^2 is 25, but i don't know how to show how to solve it All you need to do is what you just did: Explain that if x = 1, the equation is satisfied. … 
Math
Help with these problems would be greatly appreciated: 1.Find the definite integral of dx/(x(1+ln(x))from e^6 to 1. 2. Solve for x in terms of k for log[2,x^6)+log[2,x^10=k. (its log base 2) 3.Solve log base 3(log base 3, x)=2 
Algebra 2
How would I solve the equation: log(base2)4  log(base2)(x+3) = log(base2)8 ? 
Algebra 2
solve the equation: log(base2)^(x3)log(base2)^5 = 2log(base2)^10 I don't know how to solve it, can someone help me? 
math
Logarithm!!! Select all of the following that are true statements: (a) log(2x) = log(2) + log(x) (b) log(3x) = 3 log(x) (c) log(12y) = 2 log(2) + log(3y) (d) log(5y) = log(20y) – log(4) (e) log(x) = log(5x) – log(5) (f) ln(25) … 
PrecalculusVerify
log(base2)xlog(base2)6= log(base2)5+ 2log(base2)3 log(x/6)=3log15 (x/6)=15^3 6*(x/6)=15^3*6 x=15^3*6 =20,250 Answer is 270.... What did I do wrong... 
Algebra
In the logarithmic expression . . . log(base 4) 8 , how does the base 4 become base 2? 
Advanced Functions/ Precalculus Log
1. Evaluate 4^(log base4 64) + 10^(log100) 2. Write 1+log(base2)x^3 as a single logarithm 3. Write log(base b)√(x^3 y z^6) 4. Solve log(base 2)xlog(base 2)6=log(base 2)5+2log(base 2)3 5. Solve 3^(2x) = 9(81^x) 6. Solve 3^(2x)=7^(3x1). … 
math
Given that 2 log base2 (x+15)  log base2 x = 6 1.Show that x^2 34x +225 = 0 2. Hence or otherwise solve the equation 2 log base 2 (x+15)  log base 2 x =6