calculus

posted by .

Find area of the region under the curve y = 5 x^3 - 9 and above the x-axis, for 3¡Ü x ¡Ü 6. area = ??

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Calculus

    Integrals: When we solve for area under a curve, we must consider when the curve is under the axis. We would have to split the integral using the zeros that intersect with the axis. Would this be for all integrals?
  2. Pre-Calc

    Can anyone help with the following problem please...Thank u so much Let f(x) =|9x|. For the area above the x-axis and between the lines x= -9 and x=18 a. draw and label a sketch with the area shaded b. find the area of the region in …
  3. Calculus

    These are the two problems from my homework I don't get.. can you help me?
  4. Calculus

    1. Find the area of the region bounded by the curves and lines y=e^x sin e^x, x=0, y=0, and the curve's first positive intersection with the x-axis. 2. The area under the curve of y=1/x from x=a to x=5 is approximately 0.916 where …
  5. Fundamental Theorm of Calculus

    Use a definite integral to find area of the region under the curve y=7-4x^2 and above the x-axis. Thanks in advance!
  6. Calculus

    Find the area cut off by x+y=3 from xy=2. I have proceeded as under: y=x/2. Substituting this value we get x+x/2=3 Or x+x/2-3=0 Or x^2-3x+2=0 Or (x-1)(x-2)=0, hence x=1 and x=2 are the points of intersection of the curve xy=2 and the …
  7. Math

    Find area of the region under the curve y=9−2x2 and above the x-axis. area=?
  8. calculus

    I'm having trouble on this question: Find the area of the region in the first quadrant that is bounded above by the curve y= sq rt x and below by the x-axis and the line y=x -2.
  9. Math -Calculus

    Hi, I need help with the problem: "Use a definite integral to find the area of the region under the curve y=6-4x^2 and above the x-axis". I keep getting stuck at 6x-(4x^3/3). Thanks!!
  10. Calc

    R is the region below the curve y=x and above the z-axis from x=0 to x=b, where b is a positive constant. S is the region below the curve y=cos(x) and above the x-axis from x=0 to x=b. For what value of b is the area of R equal to …

More Similar Questions