posted by d-boe .
The diagonals of rhombus FGHJ intersect at point C. If side GH is equal to x + 9 and side JH is equal to 5x – 2, find x.
a rhombus is a a quad with 4 equal sides.
So if you have followed the convention of naming the vertices in either a clockwise or couter-clockwise fashion, then both GH and JH are sides of the rhombus
so 5x-2 = x+9
4x = 11
x = 11/4 = 2.75
The fact that the diagonals intersect at C appears redundant information.