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A chemistry student weighs out 0.172 grams of acrylic acid (HCH2CHCO2) into a volumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid with 0.1800 moles/liter NaOH solution.

Calculate the volume of NaOH solution the student will need to add to reach the equivalence point.

  • chemistry -

    moles acrylic acid = grams/molar mass
    moles acrylic acid = moles NaOH.
    M NaOH = moles NaOH/L NaOH.
    You know M NaOH and moles NaOH, solve for L NaOH and convert to mL.

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