posted by Lucas .
A chemistry student weighs out 0.172 grams of acrylic acid (HCH2CHCO2) into a volumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid with 0.1800 moles/liter NaOH solution.
Calculate the volume of NaOH solution the student will need to add to reach the equivalence point.
moles acrylic acid = grams/molar mass
moles acrylic acid = moles NaOH.
M NaOH = moles NaOH/L NaOH.
You know M NaOH and moles NaOH, solve for L NaOH and convert to mL.