# Hard Math

posted by .

Why are these poor models for a parabola, Where a ball starts a a certain point and then is hit to reach a maximum height (vertex) and then lands at a certain point

i. y = -0.002x(x - 437.1)
ii. y = -0.5x + 216x + 3
iii. y = -0.002x + 0.879x + 3.981
iv. y = -0.002x + 0.8732x - 3.981

Thanks!

## Similar Questions

1. ### math

A parabola has the equation y = 4(x-3)^2-7 Choose 2 true statements: A) The parabola has a minimum value B) The parabola has a maximum value C) The parabola does not cross the y-axis D) The parabola does not cross the x-axis E) The …
2. ### math

A parabola has the equation y = 4(x-3)^2-7 Choose 2 true statements: A) The parabola has a minimum value B) The parabola has a maximum value C) The parabola does not cross the y-axis D) The parabola does not cross the x-axis E) The …
3. ### Physics

A regulation volleyball court is L = 18.0 m long and a regulation volleyball net is d = 2.43 m high. A volleyball player strikes the ball a height h = 1.76 m directly above the back line, and the ball's initial velocity makes an angle …
4. ### Physics

A regulation volleyball court is L = 18.0 m long and a regulation volleyball net is d = 2.43 m high. A volleyball player strikes the ball a height h = 1.76 m directly above the back line, and the ball's initial velocity makes an angle …
5. ### Physics

A tennis player hits a ball at ground level, giving it an initial velocity of 24 m/s at 57 degrees above the horizontal. (a) what are the horizontal and verticla components of the ball;s initial velocity?
6. ### algebra

So if the distance and height are reachable, why are these equations poor models of hitting a baseball: y = -0.5x^2 + 216x + 3 y = -0.002x^2 + 0.879x + 3.981 y = -0.002x^2 + 0.8732x - 3.981
7. ### Math

A person standing close to the edge on the top of a 160-foot building throws a baseball vertically upward. The quadratic function s(t) = -16t^2 +64t + 160 models the ball's height above the ground, s(t), in feet, t seconds after it …