the short side of an isosceles triangle is 16cm long increasing each side length by 24cm doubles the perimeter. how long are the other sides of the original triangle?
Ok so......
If you're in grade 6 this should be easy
Since the bottom side is 16 that means you have to find out the other sides( they're iscoceles so they're the same) you do
24+24+24= 72 -16 = 56. Then you want to know the other sides so you do 56 divided by 2 (the amount of sides you need to figure out)and you'll get 28 which is the number of sides. So 28 + 28 + 16 = 72 so that's the old perimeter. the new one idk
Hm, yeah I just searched this up on the web...im stuck Xp
i meant im stuck too
16 + 2s = old perimeter
16+24 + 2(s+24) = 2(16+2s)
40 + 2s + 48 = 32 + 4s
2s = 56
s = 28
so, the old perimeter was 16+2*28 = 72
the new perimeter is 40 + 2*52 = 148
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To find the lengths of the other sides of the original isosceles triangle, we can use the information given.
Let's assume that the length of the two congruent sides of the original triangle is 'x' cm. Since it is an isosceles triangle, both sides will have the same length.
According to the question, the short side of the triangle is 16 cm long. Therefore, we can set up the equation:
16 + x + x = perimeter of the original triangle
The given information also states that increasing each side length by 24 cm doubles the perimeter. So, we can set up another equation:
2 * (16 + 24 + x + 24 + x) = perimeter of the original triangle
Now, let's solve these equations to find the length of the other sides:
Equation 1: 16 + x + x = perimeter of the original triangle
Simplifying, we have:
16 + 2x = perimeter of the original triangle ...(Equation A)
Equation 2: 2 * (16 + 24 + x + 24 + x) = perimeter of the original triangle
Simplifying, we have:
2(64 + 2x) = perimeter of the original triangle
128 + 4x = perimeter of the original triangle ...(Equation B)
Since the perimeter of the original triangle is the same in both equations A and B, we can equate them:
16 + 2x = 128 + 4x
Simplifying and solving for 'x':
4x - 2x = 128 - 16
2x = 112
x = 56
Therefore, the lengths of the congruent sides of the original isosceles triangle are 56 cm.