Math
posted by Alexa .
the short side of an isosceles triangle is 16cm long increasing each side length by 24cm doubles the perimeter. how long are the other sides of the original triangle?

16 + 2s = old perimeter
16+24 + 2(s+24) = 2(16+2s)
40 + 2s + 48 = 32 + 4s
2s = 56
s = 28
so, the old perimeter was 16+2*28 = 72
the new perimeter is 40 + 2*52 = 148 
idk

Ok so......
If you're in grade 6 this should be easy
Since the bottom side is 16 that means you have to find out the other sides( they're iscoceles so they're the same) you do
24+24+24= 72 16 = 56. Then you want to know the other sides so you do 56 divided by 2 (the amount of sides you need to figure out)and you'll get 28 which is the number of sides. So 28 + 28 + 16 = 72 so that's the old perimeter. the new one idk
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