MATH
posted by Amir .
THE LINE Y=X+4 INTERSECTS THE CURVE
2X^2 + 3XY  Y^2 + 1 = 0

So it does.
use substitution to solve ...
2x^2 + 3x(x+4)  (x+4)^2 + 1 = 0
2x^2 + 3x^2 + 12x  x^2  8x  16 + 1 = 0
4x^2 + 4x  15 = 0
(2x3)(2x+5) = 0
I am sure you can finish it.
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