Straight Lines
posted by Kewal .
The axes being inclined at an angle of 30°, find the equation to the straight line
which passes through the point(2,3) and is perpendicular to the straight line
y + 3x = 6

given line 3x+y=6.
slope=3.slope of another line is 1/3.
slope point equation (yY)=m(xX).
given point (2,3).
y3=1/3(x+2).
3y9=x+2.
x3y+11=0
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