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A skateboarder, starting from rest, rolls down a 12.5-m ramp. When she arrives at the bottom of the ramp her speed is 6.45 m/s.
(a) Determine the magnitude of her acceleration, assumed to be constant.

  • Physics -

    V = sqrt(2 a X) applies when the starting velocity is zero. , therefore

    a = V^2/(2 X)= 1.664 m/s^2

    Here's how you can derive it (if you can't remember it).

    Average velocity = V/2
    Time T = X/(V/2) = 2 X/V
    Acceleration a = V/T = V^2/(2 X)

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