Post a New Question

Algebra

posted by .

find the LCM of y^2+6y+9 and y^2+y-6

  • Algebra -

    y^3+6y^2+9y=Y*(Y^2+6Y+9)=Y*(Y+3)^2
    y^2-6y=Y*(Y-6)
    The unique factors are therefore Y, (Y+3)^2 & (Y-6)
    Y*(Y+3)^2*(Y-6) is the lcm

  • Algebra -

    y^2 + 6y + 9
    = (y+3)^2

    y^2 + y - 6
    = (y+3)(y-2)

    so LCM = (y-2)(y+3)^2

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question