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find the coefficient of x^5 in the expansion (x+2)(x+1)^8

  • MATH -

    x* (x+1)^8
    +
    2(x+1)^8
    so
    find coef of x^4 in (x+1)^8
    find 2*coef of x^5 in (x+1)^*
    add them

  • MATH -

    from binomial coefficient table
    (x+1)^8 = x^8 ..... 56x^5+70x^4....+1
    so 70 + 2(56) = 182

  • MATH -

    182 is the final answer? Thank you for your help.

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