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A woman pushes a crate along the floor of a warehouse with a force of 31.9 N directed downward at an angle of 23.6° from the horizontal. If the crate has a mass of 11.9 kg and the coefficient of friction is 0.0975, find...
(a) the force of friction
b. (b) theacceleration

  • physics -

    Wc = mg = 11.9 kg * 9.8 N/kg = 116.6 N=
    Weight of crate.

    Fc = 116.6 N @ (0) Deg.=Force of crate.
    Fp = 116.6*sin(0) = 0 = Force parallel to floor.
    Fv = 116.6*cos(0) = 116.6 N. = Force
    perpendicular to floor.

    a. Ff = u*(Fv+31.9*sin23.6),
    Ff = 0.0975*(116.6+12.77) = 12.61 N.

    Fn = Fap - Fp - Ff,
    Fn = 31.9*cos23.6 - 0 - 12.61=16.62 N.
    = Net force.

    b. a = Fn/m = 16.62 / 11.9 = 1.397.

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