Trigonometry
posted by Chris .
In a right triangle, CT = 6, CA = 3, and m<CAT = 90. What is the value of cot C ?
CT= hypo
CA= Opp.

AT = √(369) = 3√3
cotC = adj/opp = CA/AT = 3/3√3 = 1/√3
you will note that for the side opposite to angle C, point C cannot be one of the endpoints.