physics

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A ball is dropped from a height of 1.5m. how long will it take the ball to reach the ground and what velocity will it reach?

  • physics -

    x = x(initial) + v(initial)t + 1/2 at^2
    0 = 1.5 + 0 + 1/2 (-10)t^2
    1.5 = 5 t^2
    t = 0.55 seconds

    v = v(initial) + at
    v = 0 + (-10)(0.55)
    v = -5.5 m/s (i.e. it will reach the ground at 5.5 m/s)

  • physics -

    I didn't get anything of what you just wrote here.

  • physics -

    s = u + 1/2(a) t^2
    1.5 = 0m/s + 1/2 (10 or 9.81) * t^2
    1.5 = 1/2 (10 or 9.81~) * t^2
    √(1.5/(1/2 (10 or 9.81)))

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