Factor (15a squared bc squared -9a squared b to the fourth c) by finding the gcf. I think the answer is 3abc(5ac-3ab3). I got it because I found the gcf of the coefficents which are 3. I subtracted one from each exponent so, i canceled …
simplify the following expression and show your problem solving strategy x cubed + x squared + x + 1 + 2(x cubed + x squared + x + 1) + 3(x cubed + x squared + x + 1) + ....100( x cubed + x squared + x + 1)
find f(a), if f(t) = 2t2(squared)-t-2 A. 2(a+t)2(squared)-2t+1-2 B. 2(t+a)2(squared)-2(t+a)-2 C. 2a2(squared)-a-2 D. 4a2(squared)-2a-2 I put (squared) because the two in front of it means it's being squared... please help. thanks!
I am so stuck on this factoring thing. how do you solve: 1)15a(squared)b-10ab(squared) 2)x(squared)-8x-8 3) 6p(squared)-17p-45 4)2r(cubed)+250 5)x(to the 6th power)-64 6)x(squared)-xy+2x-2y 7)x(to 4th power)-1