algebra 1
posted by Rosaura .
What is the solution to 2x+5y=1 and 3x+2y=11 by using elimination method

2x + 5y = 1
3x + 2y = 11
6x + 15y = 3
6x + 4y = 22
19y = 19
y=1
so,
x=3
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