# 10th chem

posted by .

Describe, in detail, how to make 3.0 liters of a 3.5 molar HCl solution from an 18.5 molar HCl stock solution.

• 10th chem -

L x M = L x M
3.0 x 3.5 = L x 18.5
L = 0.567.
Add exactly 0.567 L of the 18.5M solution to a 3.0 L volumetric flask. Add water to the mark. Mix thoroughly.

• 10th chem -

secant line

## Similar Questions

1. ### Chemistry

Describe, in detail, how to make 5.5 liters of a 2.5 molar HCl solution from a 10.5 molar HCl stock solution.
2. ### Chemistry

Please help me with these! Thanks :) Describe, in detail, how to make 5.5 liters of a 2.5 molar HCl solution from a 10.5 molar HCl stock solution. How many grams of a stock solution that is 85.5 percent H2SO4 by mass would be needed …
3. ### chem

How many liters of 12.3 molar NaOH stock solution will be needed to make 12.4 liters of a 1.2 molar NaOH solution?
4. ### Chemistry

how would I make 5.5 liters of a 2.5 molar HCl solution from a 10.5 molar HCl stock solution?
5. ### chem

Describe, in detail, how to make 3.0 liters of a 3.5 molar HCl solution from an 18.5 molar HCl stock solution.
6. ### chem

Describe in detail by words how to prepare 200ml of .150M HCl from a 1.00 M HCl stock solution?
7. ### chem

a.)How many moles of NaOH are required to prepare 2.00L od 0.380M solution?
8. ### chemistry

how to make 3.0 liters of a 0.98 molar HCl solution from a 10.5 molar HCl stock solution.
9. ### Chemistry HW!!!

1. If I dilute 75 mL of 0.50 M CaF2 solution to a final volume of 375 mL, what will be the molarity of the resulting solution?
10. ### AP CHEM

If 488 mL of 2.9 molar HCl solution is added to 191 mL of 2.8 molar Ba(OH)2 solution, what will be the molarity of BaCl2 in the resulting solution?

More Similar Questions