Trig
posted by Don .
(x+3)^2/4^2 + (y2)^2/5^2
The location of the Foci are at:
a.(3,1) and (3,5)
b. (3,2) and (3,5)
c. (3,3) and (3,7)
d. (3,1) and (3,5)
I get (3,2) and (3,5) Am I correct?

Trig 
Reiny
Why did you label this "trig" ?
Your expression should be an equation if it is to represent either an ellipse or a hyperbola.
Should it be
....... = 1 ?
secondly, you have "bouncing exponents"
What is (x+3)^2/4^2 supposed to say?
the way you typed it, it would simplify to (x+3)
check and correct your typing.
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